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链接: 二叉搜索树与双向链表

题目描述

算法分析

编程代码

/*
struct TreeNode {int val;struct TreeNode *left;struct TreeNode *right;TreeNode(int x) :val(x), left(NULL), right(NULL) {}
};*/
class Solution {
public:void InOrder(TreeNode* root,TreeNode*& pre){if(root == nullptr){return;}InOrder(root->left,pre);root->left = pre;if(pre){pre->right = root;}pre = root;InOrder(root->right,pre);}TreeNode* Convert(TreeNode* pRootOfTree) {if(pRootOfTree == nullptr){return pRootOfTree;}TreeNode* pre = nullptr;InOrder(pRootOfTree,pre);while(pRootOfTree->left){pRootOfTree = pRootOfTree->left;}return pRootOfTree;}
};